Base | Representation |
---|---|
bin | 1011111100000011100001… |
… | …0101011111010110110001 |
3 | 1201110212102221221112001101 |
4 | 2333000320111133112301 |
5 | 3210030243443323004 |
6 | 43530100253404401 |
7 | 2523230365243366 |
oct | 277007025372661 |
9 | 51425387845041 |
10 | 13126365214129 |
11 | 4200950a61462 |
12 | 157bb89199701 |
13 | 742a707c067b |
14 | 33546888846d |
15 | 17b6a8366ba4 |
hex | bf03855f5b1 |
13126365214129 has 2 divisors, whose sum is σ = 13126365214130. Its totient is φ = 13126365214128.
The previous prime is 13126365214073. The next prime is 13126365214243. The reversal of 13126365214129 is 92141256362131.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 13126295658529 + 69555600 = 3623023^2 + 8340^2 .
It is an emirp because it is prime and its reverse (92141256362131) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 13126365214129 - 29 = 13126365213617 is a prime.
It is not a weakly prime, because it can be changed into another prime (13126365214829) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6563182607064 + 6563182607065.
It is an arithmetic number, because the mean of its divisors is an integer number (6563182607065).
Almost surely, 213126365214129 is an apocalyptic number.
It is an amenable number.
13126365214129 is a deficient number, since it is larger than the sum of its proper divisors (1).
13126365214129 is an equidigital number, since it uses as much as digits as its factorization.
13126365214129 is an evil number, because the sum of its binary digits is even.
The product of its digits is 466560, while the sum is 46.
The spelling of 13126365214129 in words is "thirteen trillion, one hundred twenty-six billion, three hundred sixty-five million, two hundred fourteen thousand, one hundred twenty-nine".
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