Base | Representation |
---|---|
bin | 1011111100000011100001… |
… | …0101011111011000100011 |
3 | 1201110212102221221112012121 |
4 | 2333000320111133120203 |
5 | 3210030243443323433 |
6 | 43530100253405111 |
7 | 2523230365243621 |
oct | 277007025373043 |
9 | 51425387845177 |
10 | 13126365214243 |
11 | 4200950a61556 |
12 | 157bb89199797 |
13 | 742a707c0738 |
14 | 335468888511 |
15 | 17b6a8366c2d |
hex | bf03855f623 |
13126365214243 has 2 divisors, whose sum is σ = 13126365214244. Its totient is φ = 13126365214242.
The previous prime is 13126365214129. The next prime is 13126365214247. The reversal of 13126365214243 is 34241256362131.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 13126365214243 - 225 = 13126331659811 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 13126365214243.
It is not a weakly prime, because it can be changed into another prime (13126365214247) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6563182607121 + 6563182607122.
It is an arithmetic number, because the mean of its divisors is an integer number (6563182607122).
Almost surely, 213126365214243 is an apocalyptic number.
13126365214243 is a deficient number, since it is larger than the sum of its proper divisors (1).
13126365214243 is an equidigital number, since it uses as much as digits as its factorization.
13126365214243 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 622080, while the sum is 43.
The spelling of 13126365214243 in words is "thirteen trillion, one hundred twenty-six billion, three hundred sixty-five million, two hundred fourteen thousand, two hundred forty-three".
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