Base | Representation |
---|---|
bin | 1011111100000011100100… |
… | …1111001101010110100101 |
3 | 1201110212111000102020100102 |
4 | 2333000321033031112211 |
5 | 3210030311332012431 |
6 | 43530101553553445 |
7 | 2523230640662066 |
oct | 277007117152645 |
9 | 51425430366312 |
10 | 13126380344741 |
11 | 42009595562a4 |
12 | 157bb92275885 |
13 | 742a7398a5b1 |
14 | 33546a8a656d |
15 | 17b6a9854dcb |
hex | bf0393cd5a5 |
13126380344741 has 2 divisors, whose sum is σ = 13126380344742. Its totient is φ = 13126380344740.
The previous prime is 13126380344731. The next prime is 13126380344821. The reversal of 13126380344741 is 14744308362131.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 11530466087716 + 1595914257025 = 3395654^2 + 1263295^2 .
It is an emirp because it is prime and its reverse (14744308362131) is a distict prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-13126380344741 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (13126380344731) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6563190172370 + 6563190172371.
It is an arithmetic number, because the mean of its divisors is an integer number (6563190172371).
Almost surely, 213126380344741 is an apocalyptic number.
It is an amenable number.
13126380344741 is a deficient number, since it is larger than the sum of its proper divisors (1).
13126380344741 is an equidigital number, since it uses as much as digits as its factorization.
13126380344741 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1161216, while the sum is 47.
The spelling of 13126380344741 in words is "thirteen trillion, one hundred twenty-six billion, three hundred eighty million, three hundred forty-four thousand, seven hundred forty-one".
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