Base | Representation |
---|---|
bin | 1011111100000011111010… |
… | …1010011001001011100111 |
3 | 1201110212201100200010220201 |
4 | 2333000332222121023213 |
5 | 3210031003131412114 |
6 | 43530115004411331 |
7 | 2523233124402316 |
oct | 277007652311347 |
9 | 51425640603821 |
10 | 13126471357159 |
11 | 42009a5969276 |
12 | 157bbb8846b47 |
13 | 742a897a52b4 |
14 | 3354789d827d |
15 | 17b6b2831874 |
hex | bf03ea992e7 |
13126471357159 has 2 divisors, whose sum is σ = 13126471357160. Its totient is φ = 13126471357158.
The previous prime is 13126471357141. The next prime is 13126471357169. The reversal of 13126471357159 is 95175317462131.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 13126471357159 - 221 = 13126469260007 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (13126471357169) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6563235678579 + 6563235678580.
It is an arithmetic number, because the mean of its divisors is an integer number (6563235678580).
Almost surely, 213126471357159 is an apocalyptic number.
13126471357159 is a deficient number, since it is larger than the sum of its proper divisors (1).
13126471357159 is an equidigital number, since it uses as much as digits as its factorization.
13126471357159 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 4762800, while the sum is 55.
The spelling of 13126471357159 in words is "thirteen trillion, one hundred twenty-six billion, four hundred seventy-one million, three hundred fifty-seven thousand, one hundred fifty-nine".
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