Base | Representation |
---|---|
bin | 1011111100000011111010… |
… | …1100011001001010111111 |
3 | 1201110212201101122210001022 |
4 | 2333000332230121022333 |
5 | 3210031003300201112 |
6 | 43530115023534355 |
7 | 2523233132014613 |
oct | 277007654311277 |
9 | 51425641583038 |
10 | 13126471881407 |
11 | 42009a6197135 |
12 | 157bbb8a5a3bb |
13 | 742a89929ac1 |
14 | 335478ad3343 |
15 | 17b6b28d6d72 |
hex | bf03eb192bf |
13126471881407 has 2 divisors, whose sum is σ = 13126471881408. Its totient is φ = 13126471881406.
The previous prime is 13126471881371. The next prime is 13126471881437. The reversal of 13126471881407 is 70418817462131.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 13126471881407 - 226 = 13126404772543 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (13126471881437) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6563235940703 + 6563235940704.
It is an arithmetic number, because the mean of its divisors is an integer number (6563235940704).
Almost surely, 213126471881407 is an apocalyptic number.
13126471881407 is a deficient number, since it is larger than the sum of its proper divisors (1).
13126471881407 is an equidigital number, since it uses as much as digits as its factorization.
13126471881407 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1806336, while the sum is 53.
The spelling of 13126471881407 in words is "thirteen trillion, one hundred twenty-six billion, four hundred seventy-one million, eight hundred eighty-one thousand, four hundred seven".
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