Base | Representation |
---|---|
bin | 10011000110100000011… |
… | …011011001011111010011 |
3 | 11122111012021220102111120 |
4 | 103012200123121133103 |
5 | 133001310034442011 |
6 | 2443005345413323 |
7 | 163556565452415 |
oct | 23064033313723 |
9 | 4574167812446 |
10 | 1312656562131 |
11 | 4667704546a2 |
12 | 19249a03a243 |
13 | 96a2429ca65 |
14 | 477664749b5 |
15 | 2422a137a06 |
hex | 131a06d97d3 |
1312656562131 has 4 divisors (see below), whose sum is σ = 1750208749512. Its totient is φ = 875104374752.
The previous prime is 1312656562127. The next prime is 1312656562153.
It is a happy number.
1312656562131 is nontrivially palindromic in base 10.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 1312656562131 - 22 = 1312656562127 is a prime.
It is a super-2 number, since 2×13126565621312 (a number of 25 digits) contains 22 as substring.
It is not an unprimeable number, because it can be changed into a prime (1312656562121) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 218776093686 + ... + 218776093691.
It is an arithmetic number, because the mean of its divisors is an integer number (437552187378).
Almost surely, 21312656562131 is an apocalyptic number.
1312656562131 is a deficient number, since it is larger than the sum of its proper divisors (437552187381).
1312656562131 is an equidigital number, since it uses as much as digits as its factorization.
1312656562131 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 437552187380.
The product of its digits is 194400, while the sum is 42.
The spelling of 1312656562131 in words is "one trillion, three hundred twelve billion, six hundred fifty-six million, five hundred sixty-two thousand, one hundred thirty-one".
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