Base | Representation |
---|---|
bin | 11000011100111011… |
… | …10111011011100011 |
3 | 1020212212220210101201 |
4 | 30032131313123203 |
5 | 203341132042011 |
6 | 10010350142031 |
7 | 643212601444 |
oct | 141635673343 |
9 | 36785823351 |
10 | 13127612131 |
11 | 5627216327 |
12 | 26644b1917 |
13 | 131296263a |
14 | 8c76a72cb |
15 | 51c75ccc1 |
hex | 30e7776e3 |
13127612131 has 2 divisors, whose sum is σ = 13127612132. Its totient is φ = 13127612130.
The previous prime is 13127612053. The next prime is 13127612209. The reversal of 13127612131 is 13121672131.
It is a balanced prime because it is at equal distance from previous prime (13127612053) and next prime (13127612209).
It is a cyclic number.
It is not a de Polignac number, because 13127612131 - 219 = 13127087843 is a prime.
It is a super-2 number, since 2×131276121312 (a number of 21 digits) contains 22 as substring.
It is a self number, because there is not a number n which added to its sum of digits gives 13127612131.
It is not a weakly prime, because it can be changed into another prime (13127612731) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6563806065 + 6563806066.
It is an arithmetic number, because the mean of its divisors is an integer number (6563806066).
Almost surely, 213127612131 is an apocalyptic number.
13127612131 is a deficient number, since it is larger than the sum of its proper divisors (1).
13127612131 is an equidigital number, since it uses as much as digits as its factorization.
13127612131 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 1512, while the sum is 28.
The spelling of 13127612131 in words is "thirteen billion, one hundred twenty-seven million, six hundred twelve thousand, one hundred thirty-one".
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