Base | Representation |
---|---|
bin | 1011111100010001000100… |
… | …1011010011110011011010 |
3 | 1201111012211111110102011211 |
4 | 2333010101023103303122 |
5 | 3210110221304414432 |
6 | 43531501252213334 |
7 | 2523416501520664 |
oct | 277042113236332 |
9 | 51435744412154 |
10 | 13130003201242 |
11 | 4202448565a84 |
12 | 158082360a24a |
13 | 743200411075 |
14 | 3356d1ac5534 |
15 | 17b81c92dd47 |
hex | bf1112d3cda |
13130003201242 has 4 divisors (see below), whose sum is σ = 19695004801866. Its totient is φ = 6565001600620.
The previous prime is 13130003201239. The next prime is 13130003201243. The reversal of 13130003201242 is 24210230003131.
It is a semiprime because it is the product of two primes.
It can be written as a sum of positive squares in only one way, i.e., 11019140001081 + 2110863200161 = 3319509^2 + 1452881^2 .
It is not an unprimeable number, because it can be changed into a prime (13130003201243) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 3282500800309 + ... + 3282500800312.
Almost surely, 213130003201242 is an apocalyptic number.
13130003201242 is a deficient number, since it is larger than the sum of its proper divisors (6565001600624).
13130003201242 is an equidigital number, since it uses as much as digits as its factorization.
13130003201242 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 6565001600623.
The product of its (nonzero) digits is 864, while the sum is 22.
Adding to 13130003201242 its reverse (24210230003131), we get a palindrome (37340233204373).
The spelling of 13130003201242 in words is "thirteen trillion, one hundred thirty billion, three million, two hundred one thousand, two hundred forty-two".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.070 sec. • engine limits •