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131300112100331 is a prime number
BaseRepresentation
bin11101110110101010110000…
…100010100110101111101011
3122012220011112120022000202002
4131312222300202212233223
5114202210112144202311
61143130234440201215
736441056115213236
oct3566526042465753
9565804476260662
10131300112100331
1138922079326019
1212886a11a6920b
13583571696b985
14245cd605a841d
15102a63d26393b
hex776ab08a6beb

131300112100331 has 2 divisors, whose sum is σ = 131300112100332. Its totient is φ = 131300112100330.

The previous prime is 131300112100301. The next prime is 131300112100387. The reversal of 131300112100331 is 133001211003131.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 131300112100331 - 238 = 131025234193387 is a prime.

It is a super-2 number, since 2×1313001121003312 (a number of 29 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (131300112100301) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65650056050165 + 65650056050166.

It is an arithmetic number, because the mean of its divisors is an integer number (65650056050166).

Almost surely, 2131300112100331 is an apocalyptic number.

131300112100331 is a deficient number, since it is larger than the sum of its proper divisors (1).

131300112100331 is an equidigital number, since it uses as much as digits as its factorization.

131300112100331 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 162, while the sum is 20.

Adding to 131300112100331 its reverse (133001211003131), we get a palindrome (264301323103462).

The spelling of 131300112100331 in words is "one hundred thirty-one trillion, three hundred billion, one hundred twelve million, one hundred thousand, three hundred thirty-one".