131300112100301 has 2 divisors, whose sum is σ = 131300112100302. Its totient is φ = 131300112100300.

The previous prime is 131300112100291. The next prime is 131300112100331. The reversal of 131300112100301 is 103001211003131.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 106925402544676 + 24374709555625 = 10340474^2 + 4937075^2 .

It is a cyclic number.

It is not a de Polignac number, because 131300112100301 - 2⁴² = 126902065589197 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 131300112100301.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (131300112100331) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65650056050150 + 65650056050151.

It is an arithmetic number, because the mean of its divisors is an integer number (65650056050151).

Almost surely, 2^{131300112100301} is an apocalyptic number.

It is an amenable number.

131300112100301 is a deficient number, since it is larger than the sum of its proper divisors (1).

131300112100301 is an equidigital number, since it uses as much as digits as its factorization.

131300112100301 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 54, while the sum is 17.

Adding to 131300112100301 its reverse (103001211003131), we get a palindrome (234301323103432).

The spelling of 131300112100301 in words is "one hundred thirty-one trillion, three hundred billion, one hundred twelve million, one hundred thousand, three hundred one".