Base | Representation |
---|---|
bin | 11101110110101010110000… |
… | …100010100110111010011111 |
3 | 122012220011112120022001200201 |
4 | 131312222300202212322133 |
5 | 114202210112144213043 |
6 | 1143130234440204331 |
7 | 36441056115215245 |
oct | 3566526042467237 |
9 | 565804476261621 |
10 | 131300112101023 |
11 | 38922079326598 |
12 | 12886a11a696a7 |
13 | 583571696c098 |
14 | 245cd605a8795 |
15 | 102a63d263c4d |
hex | 776ab08a6e9f |
131300112101023 has 2 divisors, whose sum is σ = 131300112101024. Its totient is φ = 131300112101022.
The previous prime is 131300112101009. The next prime is 131300112101047. The reversal of 131300112101023 is 320101211003131.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 131300112101023 - 217 = 131300111969951 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (131300112101063) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65650056050511 + 65650056050512.
It is an arithmetic number, because the mean of its divisors is an integer number (65650056050512).
Almost surely, 2131300112101023 is an apocalyptic number.
131300112101023 is a deficient number, since it is larger than the sum of its proper divisors (1).
131300112101023 is an equidigital number, since it uses as much as digits as its factorization.
131300112101023 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 108, while the sum is 19.
Adding to 131300112101023 its reverse (320101211003131), we get a palindrome (451401323104154).
The spelling of 131300112101023 in words is "one hundred thirty-one trillion, three hundred billion, one hundred twelve million, one hundred one thousand, twenty-three".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.073 sec. • engine limits •