Base | Representation |
---|---|
bin | 10011000110110100111… |
… | …101110010110110010111 |
3 | 11122112002022020221110111 |
4 | 103012310331302312113 |
5 | 133003011241420343 |
6 | 2443103454503451 |
7 | 163601251254616 |
oct | 23066475626627 |
9 | 4575068227414 |
10 | 1313001123223 |
11 | 4669279a4529 |
12 | 192575504b87 |
13 | 96a7a7a046a |
14 | 4779a12787d |
15 | 2424a4e9c9d |
hex | 131b4f72d97 |
1313001123223 has 2 divisors, whose sum is σ = 1313001123224. Its totient is φ = 1313001123222.
The previous prime is 1313001123169. The next prime is 1313001123283. The reversal of 1313001123223 is 3223211003131.
It is a weak prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-1313001123223 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 1313001123194 and 1313001123203.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1313001123283) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 656500561611 + 656500561612.
It is an arithmetic number, because the mean of its divisors is an integer number (656500561612).
Almost surely, 21313001123223 is an apocalyptic number.
1313001123223 is a deficient number, since it is larger than the sum of its proper divisors (1).
1313001123223 is an equidigital number, since it uses as much as digits as its factorization.
1313001123223 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 648, while the sum is 22.
Adding to 1313001123223 its reverse (3223211003131), we get a palindrome (4536212126354).
The spelling of 1313001123223 in words is "one trillion, three hundred thirteen billion, one million, one hundred twenty-three thousand, two hundred twenty-three".
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