1313001131033 has 8 divisors (see below), whose sum is σ = 1405857128040. Its totient is φ = 1221880760320.

The previous prime is 1313001131021. The next prime is 1313001131051. The reversal of 1313001131033 is 3301311003131.

It can be written as a sum of positive squares in 4 ways, for example, as 72423959689 + 1240577171344 = 269117^2 + 1113812^2 .

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 1313001131033 - 2¹⁸ = 1313000868889 is a prime.

It is a Curzon number.

It is a junction number, because it is equal to n+sod(n) for n = 1313001130996 and 1313001131014.

It is not an unprimeable number, because it can be changed into a prime (1313001131003) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 433905008 + ... + 433908033.

It is an arithmetic number, because the mean of its divisors is an integer number (175732141005).

Almost surely, 2^{1313001131033} is an apocalyptic number.

It is an amenable number.

1313001131033 is a deficient number, since it is larger than the sum of its proper divisors (92855997007).

1313001131033 is an equidigital number, since it uses as much as digits as its factorization.

1313001131033 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 867813147.

The product of its (nonzero) digits is 243, while the sum is 20.

Adding to 1313001131033 its reverse (3301311003131), we get a palindrome (4614312134164).

The spelling of 1313001131033 in words is "one trillion, three hundred thirteen billion, one million, one hundred thirty-one thousand, thirty-three".