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1313001223201 is a prime number
BaseRepresentation
bin10011000110110100111…
…110001011010000100001
311122112002022110000121101
4103012310332023100201
5133003011303120301
62443103500554401
7163601252152243
oct23066476132041
94575068400541
101313001223201
11466927a62658
12192575552a01
1396a7a806b15
144779a152093
152424a519701
hex131b4f8b421

1313001223201 has 2 divisors, whose sum is σ = 1313001223202. Its totient is φ = 1313001223200.

The previous prime is 1313001223117. The next prime is 1313001223213. The reversal of 1313001223201 is 1023221003131.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 1103237223201 + 209764000000 = 1050351^2 + 458000^2 .

It is an emirp because it is prime and its reverse (1023221003131) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 1313001223201 - 217 = 1313001092129 is a prime.

It is not a weakly prime, because it can be changed into another prime (1313001523201) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 656500611600 + 656500611601.

It is an arithmetic number, because the mean of its divisors is an integer number (656500611601).

Almost surely, 21313001223201 is an apocalyptic number.

It is an amenable number.

1313001223201 is a deficient number, since it is larger than the sum of its proper divisors (1).

1313001223201 is an equidigital number, since it uses as much as digits as its factorization.

1313001223201 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 216, while the sum is 19.

Adding to 1313001223201 its reverse (1023221003131), we get a palindrome (2336222226332).

The spelling of 1313001223201 in words is "one trillion, three hundred thirteen billion, one million, two hundred twenty-three thousand, two hundred one".