1313001223117 has 2 divisors, whose sum is σ = 1313001223118. Its totient is φ = 1313001223116.

The previous prime is 1313001223081. The next prime is 1313001223201. The reversal of 1313001223117 is 7113221003131.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 1312992847881 + 8375236 = 1145859^2 + 2894^2 .

It is a cyclic number.

It is not a de Polignac number, because 1313001223117 - 2³⁹ = 763245409229 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 1313001223091 and 1313001223100.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1313001253117) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 656500611558 + 656500611559.

It is an arithmetic number, because the mean of its divisors is an integer number (656500611559).

Almost surely, 2^{1313001223117} is an apocalyptic number.

It is an amenable number.

1313001223117 is a deficient number, since it is larger than the sum of its proper divisors (1).

1313001223117 is an equidigital number, since it uses as much as digits as its factorization.

1313001223117 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 756, while the sum is 25.

Adding to 1313001223117 its reverse (7113221003131), we get a palindrome (8426222226248).

The spelling of 1313001223117 in words is "one trillion, three hundred thirteen billion, one million, two hundred twenty-three thousand, one hundred seventeen".