13130033011321 has 4 divisors (see below), whose sum is σ = 13132710975232. Its totient is φ = 13127355047412.

The previous prime is 13130033011301. The next prime is 13130033011327. The reversal of 13130033011321 is 12311033003131.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-13130033011321 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 13130033011292 and 13130033011301.

It is not an unprimeable number, because it can be changed into a prime (13130033011327) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1338974601 + ... + 1338984406.

It is an arithmetic number, because the mean of its divisors is an integer number (3283177743808).

Almost surely, 2^{13130033011321} is an apocalyptic number.

It is an amenable number.

13130033011321 is a deficient number, since it is larger than the sum of its proper divisors (2677963911).

13130033011321 is an equidigital number, since it uses as much as digits as its factorization.

13130033011321 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 2677963910.

The product of its (nonzero) digits is 486, while the sum is 22.

Adding to 13130033011321 its reverse (12311033003131), we get a palindrome (25441066014452).

The spelling of 13130033011321 in words is "thirteen trillion, one hundred thirty billion, thirty-three million, eleven thousand, three hundred twenty-one".