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13130033210111 = 91731431378307
BaseRepresentation
bin1011111100010001001011…
…1101110010001011111111
31201111012220120221000121102
42333010102331302023333
53210110302000210421
643531504243323315
72523420314554256
oct277042275621377
951435816830542
1013130033210111
1142024634a20a4
12158083168053b
137432066ba0ac
143356d5a9779d
1517b8203aa60b
hexbf112f722ff

13130033210111 has 4 divisors (see below), whose sum is σ = 13131464597592. Its totient is φ = 13128601822632.

The previous prime is 13130033210083. The next prime is 13130033210117. The reversal of 13130033210111 is 11101233003131.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-13130033210111 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (13130033210117) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 715679981 + ... + 715698326.

It is an arithmetic number, because the mean of its divisors is an integer number (3282866149398).

Almost surely, 213130033210111 is an apocalyptic number.

13130033210111 is a deficient number, since it is larger than the sum of its proper divisors (1431387481).

13130033210111 is an equidigital number, since it uses as much as digits as its factorization.

13130033210111 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1431387480.

The product of its (nonzero) digits is 162, while the sum is 20.

Adding to 13130033210111 its reverse (11101233003131), we get a palindrome (24231266213242).

The spelling of 13130033210111 in words is "thirteen trillion, one hundred thirty billion, thirty-three million, two hundred ten thousand, one hundred eleven".

Divisors: 1 9173 1431378307 13130033210111