Base | Representation |
---|---|
bin | 1011111100010001001011… |
… | …1101110010001011111111 |
3 | 1201111012220120221000121102 |
4 | 2333010102331302023333 |
5 | 3210110302000210421 |
6 | 43531504243323315 |
7 | 2523420314554256 |
oct | 277042275621377 |
9 | 51435816830542 |
10 | 13130033210111 |
11 | 42024634a20a4 |
12 | 158083168053b |
13 | 7432066ba0ac |
14 | 3356d5a9779d |
15 | 17b8203aa60b |
hex | bf112f722ff |
13130033210111 has 4 divisors (see below), whose sum is σ = 13131464597592. Its totient is φ = 13128601822632.
The previous prime is 13130033210083. The next prime is 13130033210117. The reversal of 13130033210111 is 11101233003131.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-13130033210111 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (13130033210117) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 715679981 + ... + 715698326.
It is an arithmetic number, because the mean of its divisors is an integer number (3282866149398).
Almost surely, 213130033210111 is an apocalyptic number.
13130033210111 is a deficient number, since it is larger than the sum of its proper divisors (1431387481).
13130033210111 is an equidigital number, since it uses as much as digits as its factorization.
13130033210111 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 1431387480.
The product of its (nonzero) digits is 162, while the sum is 20.
Adding to 13130033210111 its reverse (11101233003131), we get a palindrome (24231266213242).
The spelling of 13130033210111 in words is "thirteen trillion, one hundred thirty billion, thirty-three million, two hundred ten thousand, one hundred eleven".
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