Base | Representation |
---|---|
bin | 1011111100010001001110… |
… | …1100110000110101100111 |
3 | 1201111012221110002200221102 |
4 | 2333010103230300311213 |
5 | 3210110313123302401 |
6 | 43531505403310315 |
7 | 2523420524335616 |
oct | 277042354606547 |
9 | 51435843080842 |
10 | 13130045525351 |
11 | 420246a443787 |
12 | 158083581b39b |
13 | 74320910c711 |
14 | 3356d758187d |
15 | 17b8214de56b |
hex | bf113b30d67 |
13130045525351 has 4 divisors (see below), whose sum is σ = 13150152793272. Its totient is φ = 13109938257432.
The previous prime is 13130045525339. The next prime is 13130045525371. The reversal of 13130045525351 is 15352554003131.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 13130045525351 - 238 = 12855167618407 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (13130045525371) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 10053632981 + ... + 10053634286.
It is an arithmetic number, because the mean of its divisors is an integer number (3287538198318).
Almost surely, 213130045525351 is an apocalyptic number.
13130045525351 is a deficient number, since it is larger than the sum of its proper divisors (20107267921).
13130045525351 is an equidigital number, since it uses as much as digits as its factorization.
13130045525351 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 20107267920.
The product of its (nonzero) digits is 135000, while the sum is 38.
Adding to 13130045525351 its reverse (15352554003131), we get a palindrome (28482599528482).
The spelling of 13130045525351 in words is "thirteen trillion, one hundred thirty billion, forty-five million, five hundred twenty-five thousand, three hundred fifty-one".
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