Search a number
-
+
13130045525351 = 65320107267267
BaseRepresentation
bin1011111100010001001110…
…1100110000110101100111
31201111012221110002200221102
42333010103230300311213
53210110313123302401
643531505403310315
72523420524335616
oct277042354606547
951435843080842
1013130045525351
11420246a443787
12158083581b39b
1374320910c711
143356d758187d
1517b8214de56b
hexbf113b30d67

13130045525351 has 4 divisors (see below), whose sum is σ = 13150152793272. Its totient is φ = 13109938257432.

The previous prime is 13130045525339. The next prime is 13130045525371. The reversal of 13130045525351 is 15352554003131.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 13130045525351 - 238 = 12855167618407 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (13130045525371) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 10053632981 + ... + 10053634286.

It is an arithmetic number, because the mean of its divisors is an integer number (3287538198318).

Almost surely, 213130045525351 is an apocalyptic number.

13130045525351 is a deficient number, since it is larger than the sum of its proper divisors (20107267921).

13130045525351 is an equidigital number, since it uses as much as digits as its factorization.

13130045525351 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 20107267920.

The product of its (nonzero) digits is 135000, while the sum is 38.

Adding to 13130045525351 its reverse (15352554003131), we get a palindrome (28482599528482).

The spelling of 13130045525351 in words is "thirteen trillion, one hundred thirty billion, forty-five million, five hundred twenty-five thousand, three hundred fifty-one".

Divisors: 1 653 20107267267 13130045525351