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1313010020204 = 22328252505051
BaseRepresentation
bin10011000110110101011…
…111101110111101101100
311122112002220222221211022
4103012311133232331230
5133003021031121304
62443104413313312
7163601420011421
oct23066537567554
94575086887738
101313010020204
11466931a20a03
12192578495838
1396a7c596c4c
144779b3a1d48
152424b1a5ebe
hex131b57eef6c

1313010020204 has 6 divisors (see below), whose sum is σ = 2297767535364. Its totient is φ = 656505010100.

The previous prime is 1313010020183. The next prime is 1313010020219. The reversal of 1313010020204 is 4020200103131.

It is a super-2 number, since 2×13130100202042 (a number of 25 digits) contains 22 as substring.

It is an unprimeable number.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 164126252522 + ... + 164126252529.

It is an arithmetic number, because the mean of its divisors is an integer number (382961255894).

Almost surely, 21313010020204 is an apocalyptic number.

It is an amenable number.

1313010020204 is a deficient number, since it is larger than the sum of its proper divisors (984757515160).

1313010020204 is a wasteful number, since it uses less digits than its factorization.

1313010020204 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 328252505055 (or 328252505053 counting only the distinct ones).

The product of its (nonzero) digits is 144, while the sum is 17.

Adding to 1313010020204 its reverse (4020200103131), we get a palindrome (5333210123335).

The spelling of 1313010020204 in words is "one trillion, three hundred thirteen billion, ten million, twenty thousand, two hundred four".

Divisors: 1 2 4 328252505051 656505010102 1313010020204