131301133000113 has 4 divisors (see below), whose sum is σ = 175068177333488. Its totient is φ = 87534088666740.

The previous prime is 131301133000073. The next prime is 131301133000151. The reversal of 131301133000113 is 311000331103131.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is not a de Polignac number, because 131301133000113 - 2¹³ = 131301132991921 is a prime.

It is a super-2 number, since 2×131301133000113² (a number of 29 digits) contains 22 as substring.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 131301133000113.

It is not an unprimeable number, because it can be changed into a prime (131301133004113) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 21883522166683 + ... + 21883522166688.

It is an arithmetic number, because the mean of its divisors is an integer number (43767044333372).

Almost surely, 2^{131301133000113} is an apocalyptic number.

It is an amenable number.

131301133000113 is a deficient number, since it is larger than the sum of its proper divisors (43767044333375).

131301133000113 is an equidigital number, since it uses as much as digits as its factorization.

131301133000113 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 43767044333374.

The product of its (nonzero) digits is 243, while the sum is 21.

Adding to 131301133000113 its reverse (311000331103131), we get a palindrome (442301464103244).

The spelling of 131301133000113 in words is "one hundred thirty-one trillion, three hundred one billion, one hundred thirty-three million, one hundred thirteen", and thus it is an aban number.