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131301133000151 is a prime number
BaseRepresentation
bin11101110110101011101101…
…011001000001110111010111
3122012220021011201022010000112
4131312223231121001313113
5114202214210022001101
61143130524025433235
736441123322551452
oct3566535531016727
9565807151263015
10131301133000151
1138922552624184
121288705793b81b
13583584a3159ca
14245d019dd6499
15102a69cbc26bb
hex776aed641dd7

131301133000151 has 2 divisors, whose sum is σ = 131301133000152. Its totient is φ = 131301133000150.

The previous prime is 131301133000073. The next prime is 131301133000217. The reversal of 131301133000151 is 151000331103131.

It is a strong prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-131301133000151 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (131301133000451) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (29) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65650566500075 + 65650566500076.

It is an arithmetic number, because the mean of its divisors is an integer number (65650566500076).

Almost surely, 2131301133000151 is an apocalyptic number.

131301133000151 is a deficient number, since it is larger than the sum of its proper divisors (1).

131301133000151 is an equidigital number, since it uses as much as digits as its factorization.

131301133000151 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 405, while the sum is 23.

Adding to 131301133000151 its reverse (151000331103131), we get a palindrome (282301464103282).

The spelling of 131301133000151 in words is "one hundred thirty-one trillion, three hundred one billion, one hundred thirty-three million, one hundred fifty-one", and thus it is an aban number.