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13130123100000 = 2535543732191
BaseRepresentation
bin1011111100010001100001…
…0100101011111101100000
31201111020010212001220100120
42333010120110223331200
53210110443003200000
643531521214120240
72523422455611024
oct277043024537540
951436125056316
1013130123100000
1142024aa208765
1215808577b0080
1374321c200b8a
143357039b6384
1517b8282146a0
hexbf11852bf60

13130123100000 has 864 divisors, whose sum is σ = 44928472393728. Its totient is φ = 3355430400000.

The previous prime is 13130123099999. The next prime is 13130123100071. The reversal of 13130123100000 is 132103131.

13130123100000 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a super-2 number, since 2×131301231000002 (a number of 27 digits) contains 22 as substring.

It is a Harshad number since it is a multiple of its sum of digits (15).

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 143 ways as a sum of consecutive naturals, for example, 68744099905 + ... + 68744100095.

It is an arithmetic number, because the mean of its divisors is an integer number (52000546752).

Almost surely, 213130123100000 is an apocalyptic number.

13130123100000 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 13130123100000, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (22464236196864).

13130123100000 is an abundant number, since it is smaller than the sum of its proper divisors (31798349293728).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

13130123100000 is an frugal number, since it uses more digits than its factorization.

13130123100000 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 418 (or 317 counting only the distinct ones).

The product of its (nonzero) digits is 54, while the sum is 15.

Adding to 13130123100000 its reverse (132103131), we get a palindrome (13130255203131).

The spelling of 13130123100000 in words is "thirteen trillion, one hundred thirty billion, one hundred twenty-three million, one hundred thousand".