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131301311003 = 431304643413
BaseRepresentation
bin111101001001000101…
…0110000001000011011
3110112220121120200201122
41322102022300020123
54122401113423003
6140152522435455
712325524504662
oct1722212601033
9415817520648
10131301311003
1150759192375
1221544662b8b
13c4c667b445
1464d824bdd9
153637212238
hex1e922b021b

131301311003 has 4 divisors (see below), whose sum is σ = 131605954848. Its totient is φ = 130996667160.

The previous prime is 131301310999. The next prime is 131301311033. The reversal of 131301311003 is 300113103131.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 131301311003 - 22 = 131301310999 is a prime.

It is a super-2 number, since 2×1313013110032 (a number of 23 digits) contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (131301311033) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 152321276 + ... + 152322137.

It is an arithmetic number, because the mean of its divisors is an integer number (32901488712).

Almost surely, 2131301311003 is an apocalyptic number.

131301311003 is a deficient number, since it is larger than the sum of its proper divisors (304643845).

131301311003 is an equidigital number, since it uses as much as digits as its factorization.

131301311003 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 304643844.

The product of its (nonzero) digits is 81, while the sum is 17.

Adding to 131301311003 its reverse (300113103131), we get a palindrome (431414414134).

The spelling of 131301311003 in words is "one hundred thirty-one billion, three hundred one million, three hundred eleven thousand, three".

Divisors: 1 431 304643413 131301311003