Base | Representation |
---|---|
bin | 10011000110110101101… |
… | …011100001110011000001 |
3 | 11122112010010211000222022 |
4 | 103012311223201303001 |
5 | 133003022324041001 |
6 | 2443105003451225 |
7 | 163601455206413 |
oct | 23066553416301 |
9 | 4575103730868 |
10 | 1313013112001 |
11 | 466933742908 |
12 | 192579526b15 |
13 | 96a8010a306 |
14 | 4779b9689b3 |
15 | 2424b5b711b |
hex | 131b5ae1cc1 |
1313013112001 has 2 divisors, whose sum is σ = 1313013112002. Its totient is φ = 1313013112000.
The previous prime is 1313013111989. The next prime is 1313013112039. The reversal of 1313013112001 is 1002113103131.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 1060683711025 + 252329400976 = 1029895^2 + 502324^2 .
It is a cyclic number.
It is not a de Polignac number, because 1313013112001 - 234 = 1295833242817 is a prime.
It is not a weakly prime, because it can be changed into another prime (1313013117001) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 656506556000 + 656506556001.
It is an arithmetic number, because the mean of its divisors is an integer number (656506556001).
Almost surely, 21313013112001 is an apocalyptic number.
It is an amenable number.
1313013112001 is a deficient number, since it is larger than the sum of its proper divisors (1).
1313013112001 is an equidigital number, since it uses as much as digits as its factorization.
1313013112001 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 54, while the sum is 17.
Adding to 1313013112001 its reverse (1002113103131), we get a palindrome (2315126215132).
The spelling of 1313013112001 in words is "one trillion, three hundred thirteen billion, thirteen million, one hundred twelve thousand, one".
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