13130143113433 has 2 divisors, whose sum is σ = 13130143113434. Its totient is φ = 13130143113432.

The previous prime is 13130143113427. The next prime is 13130143113463. The reversal of 13130143113433 is 33431134103131.

It is a happy number.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 13077278527504 + 52864585929 = 3616252^2 + 229923^2 .

It is a cyclic number.

It is not a de Polignac number, because 13130143113433 - 2⁵ = 13130143113401 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 13130143113395 and 13130143113404.

It is not a weakly prime, because it can be changed into another prime (13130143113463) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6565071556716 + 6565071556717.

It is an arithmetic number, because the mean of its divisors is an integer number (6565071556717).

Almost surely, 2^{13130143113433} is an apocalyptic number.

It is an amenable number.

13130143113433 is a deficient number, since it is larger than the sum of its proper divisors (1).

13130143113433 is an equidigital number, since it uses as much as digits as its factorization.

13130143113433 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 11664, while the sum is 31.

Adding to 13130143113433 its reverse (33431134103131), we get a palindrome (46561277216564).

The spelling of 13130143113433 in words is "thirteen trillion, one hundred thirty billion, one hundred forty-three million, one hundred thirteen thousand, four hundred thirty-three".