Base | Representation |
---|---|
bin | 10011000110110110000… |
… | …110100101010100001111 |
3 | 11122112010122011100210011 |
4 | 103012312012211110033 |
5 | 133003031133014203 |
6 | 2443105415454051 |
7 | 163601602405603 |
oct | 23066606452417 |
9 | 4575118140704 |
10 | 1313020204303 |
11 | 466937747415 |
12 | 19257b987327 |
13 | 96a81721542 |
14 | 4779c893503 |
15 | 2424c01876d |
hex | 131b61a550f |
1313020204303 has 2 divisors, whose sum is σ = 1313020204304. Its totient is φ = 1313020204302.
The previous prime is 1313020204289. The next prime is 1313020204337. The reversal of 1313020204303 is 3034020203131.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 1313020204303 - 217 = 1313020073231 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1313020204373) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 656510102151 + 656510102152.
It is an arithmetic number, because the mean of its divisors is an integer number (656510102152).
Almost surely, 21313020204303 is an apocalyptic number.
1313020204303 is a deficient number, since it is larger than the sum of its proper divisors (1).
1313020204303 is an equidigital number, since it uses as much as digits as its factorization.
1313020204303 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1296, while the sum is 22.
Adding to 1313020204303 its reverse (3034020203131), we get a palindrome (4347040407434).
The spelling of 1313020204303 in words is "one trillion, three hundred thirteen billion, twenty million, two hundred four thousand, three hundred three".
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