Base | Representation |
---|---|
bin | 1011111100010001110110… |
… | …0000001110010100100010 |
3 | 1201111020100220121102000100 |
4 | 2333010131200032110202 |
5 | 3210111132230313102 |
6 | 43531534001003230 |
7 | 2523424562415102 |
oct | 277043540162442 |
9 | 51436326542010 |
10 | 13130210010402 |
11 | 4202544279841 |
12 | 1580880923516 |
13 | 743234210754 |
14 | 33571135b202 |
15 | 17b830b80a1c |
hex | bf11d80e522 |
13130210010402 has 36 divisors (see below), whose sum is σ = 30024898528950. Its totient is φ = 4146382106496.
The previous prime is 13130210010389. The next prime is 13130210010403. The reversal of 13130210010402 is 20401001203131.
13130210010402 is a `hidden beast` number, since 13 + 1 + 30 + 210 + 0 + 10 + 402 = 666.
It can be written as a sum of positive squares in only one way, i.e., 13027847766921 + 102362243481 = 3609411^2 + 319941^2 .
It is a Harshad number since it is a multiple of its sum of digits (18).
It is not an unprimeable number, because it can be changed into a prime (13130210010403) by changing a digit.
It is a polite number, since it can be written in 17 ways as a sum of consecutive naturals, for example, 1010320527 + ... + 1010333522.
Almost surely, 213130210010402 is an apocalyptic number.
13130210010402 is an abundant number, since it is smaller than the sum of its proper divisors (16894688518548).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
13130210010402 is a wasteful number, since it uses less digits than its factorization.
13130210010402 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 2020654095 (or 2020654073 counting only the distinct ones).
The product of its (nonzero) digits is 144, while the sum is 18.
Adding to 13130210010402 its reverse (20401001203131), we get a palindrome (33531211213533).
The spelling of 13130210010402 in words is "thirteen trillion, one hundred thirty billion, two hundred ten million, ten thousand, four hundred two".
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