Base | Representation |
---|---|
bin | 11101110110101101011110… |
… | …000011001110110000100111 |
3 | 122012220110001102212200221201 |
4 | 131312231132003032300213 |
5 | 114202232042404024312 |
6 | 1143131435345223331 |
7 | 36441221213333353 |
oct | 3566553603166047 |
9 | 565813042780851 |
10 | 131303023111207 |
11 | 38923332535632 |
12 | 128874a4931b47 |
13 | 5835a8ba9640c |
14 | 245d159048463 |
15 | 102a75daca557 |
hex | 776b5e0cec27 |
131303023111207 has 2 divisors, whose sum is σ = 131303023111208. Its totient is φ = 131303023111206.
The previous prime is 131303023111199. The next prime is 131303023111213. The reversal of 131303023111207 is 702111320303131.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 131303023111207 - 23 = 131303023111199 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (131303023111217) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65651511555603 + 65651511555604.
It is an arithmetic number, because the mean of its divisors is an integer number (65651511555604).
Almost surely, 2131303023111207 is an apocalyptic number.
131303023111207 is a deficient number, since it is larger than the sum of its proper divisors (1).
131303023111207 is an equidigital number, since it uses as much as digits as its factorization.
131303023111207 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 2268, while the sum is 28.
Adding to 131303023111207 its reverse (702111320303131), we get a palindrome (833414343414338).
The spelling of 131303023111207 in words is "one hundred thirty-one trillion, three hundred three billion, twenty-three million, one hundred eleven thousand, two hundred seven".
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