Base | Representation |
---|---|
bin | 11101110110101101100010… |
… | …010110011011101111110111 |
3 | 122012220110020110121221021021 |
4 | 131312231202112123233313 |
5 | 114202232214341112012 |
6 | 1143131450443402011 |
7 | 36441223050463255 |
oct | 3566554226335767 |
9 | 565813213557237 |
10 | 131303095254007 |
11 | 3892336a22a586 |
12 | 12887504b23307 |
13 | 5835aa0a05371 |
14 | 245d1648675d5 |
15 | 102a7650cb007 |
hex | 776b6259bbf7 |
131303095254007 has 2 divisors, whose sum is σ = 131303095254008. Its totient is φ = 131303095254006.
The previous prime is 131303095253987. The next prime is 131303095254041. The reversal of 131303095254007 is 700452590303131.
It is a weak prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-131303095254007 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (131303095254407) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (31) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65651547627003 + 65651547627004.
It is an arithmetic number, because the mean of its divisors is an integer number (65651547627004).
Almost surely, 2131303095254007 is an apocalyptic number.
131303095254007 is a deficient number, since it is larger than the sum of its proper divisors (1).
131303095254007 is an equidigital number, since it uses as much as digits as its factorization.
131303095254007 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 340200, while the sum is 43.
The spelling of 131303095254007 in words is "one hundred thirty-one trillion, three hundred three billion, ninety-five million, two hundred fifty-four thousand, seven".
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