Base | Representation |
---|---|
bin | 11101110110101101100011… |
… | …001111000110101111010011 |
3 | 122012220110021111120201002021 |
4 | 131312231203033012233103 |
5 | 114202232232142011123 |
6 | 1143131452134032311 |
7 | 36441223320656545 |
oct | 3566554317065723 |
9 | 565813244521067 |
10 | 131303110110163 |
11 | 389233776571a2 |
12 | 12887509aa8697 |
13 | 5835aa3b073a4 |
14 | 245d166813695 |
15 | 102a766562c5d |
hex | 776b633c6bd3 |
131303110110163 has 2 divisors, whose sum is σ = 131303110110164. Its totient is φ = 131303110110162.
The previous prime is 131303110110071. The next prime is 131303110110199. The reversal of 131303110110163 is 361011011303131.
It is a happy number.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 131303110110163 - 217 = 131303109979091 is a prime.
It is not a weakly prime, because it can be changed into another prime (131303110111163) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (29) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65651555055081 + 65651555055082.
It is an arithmetic number, because the mean of its divisors is an integer number (65651555055082).
Almost surely, 2131303110110163 is an apocalyptic number.
131303110110163 is a deficient number, since it is larger than the sum of its proper divisors (1).
131303110110163 is an equidigital number, since it uses as much as digits as its factorization.
131303110110163 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 486, while the sum is 25.
Adding to 131303110110163 its reverse (361011011303131), we get a palindrome (492314121413294).
The spelling of 131303110110163 in words is "one hundred thirty-one trillion, three hundred three billion, one hundred ten million, one hundred ten thousand, one hundred sixty-three".
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