131303112110033 has 4 divisors (see below), whose sum is σ = 134505627039588. Its totient is φ = 128100597180480.

The previous prime is 131303112110029. The next prime is 131303112110041. The reversal of 131303112110033 is 330011211303131.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 14666395286929 + 116636716823104 = 3829673^2 + 10799848^2 .

It is not a de Polignac number, because 131303112110033 - 2² = 131303112110029 is a prime.

It is a super-3 number, since 3×131303112110033³ (a number of 43 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 131303112109990 and 131303112110008.

It is not an unprimeable number, because it can be changed into a prime (131303112115033) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1601257464716 + ... + 1601257464797.

It is an arithmetic number, because the mean of its divisors is an integer number (33626406759897).

Almost surely, 2^{131303112110033} is an apocalyptic number.

It is an amenable number.

131303112110033 is a deficient number, since it is larger than the sum of its proper divisors (3202514929555).

131303112110033 is an equidigital number, since it uses as much as digits as its factorization.

131303112110033 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 3202514929554.

The product of its (nonzero) digits is 486, while the sum is 23.

Adding to 131303112110033 its reverse (330011211303131), we get a palindrome (461314323413164).

The spelling of 131303112110033 in words is "one hundred thirty-one trillion, three hundred three billion, one hundred twelve million, one hundred ten thousand, thirty-three".