Base | Representation |
---|---|
bin | 11101110110101101100011… |
… | …011000010101110100010111 |
3 | 122012220110021200010201011011 |
4 | 131312231203120111310113 |
5 | 114202232233301444343 |
6 | 1143131452301553051 |
7 | 36441223350362203 |
oct | 3566554330256427 |
9 | 565813250121134 |
10 | 131303112531223 |
11 | 38923378a60176 |
12 | 1288750a875787 |
13 | 5835aa4474379 |
14 | 245d166c83b03 |
15 | 102a76689029d |
hex | 776b63615d17 |
131303112531223 has 2 divisors, whose sum is σ = 131303112531224. Its totient is φ = 131303112531222.
The previous prime is 131303112531179. The next prime is 131303112531247. The reversal of 131303112531223 is 322135211303131.
It is a strong prime.
It is an emirp because it is prime and its reverse (322135211303131) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 131303112531223 - 225 = 131303078976791 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (131303112531323) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65651556265611 + 65651556265612.
It is an arithmetic number, because the mean of its divisors is an integer number (65651556265612).
Almost surely, 2131303112531223 is an apocalyptic number.
131303112531223 is a deficient number, since it is larger than the sum of its proper divisors (1).
131303112531223 is an equidigital number, since it uses as much as digits as its factorization.
131303112531223 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 9720, while the sum is 31.
Adding to 131303112531223 its reverse (322135211303131), we get a palindrome (453438323834354).
The spelling of 131303112531223 in words is "one hundred thirty-one trillion, three hundred three billion, one hundred twelve million, five hundred thirty-one thousand, two hundred twenty-three".
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