Base | Representation |
---|---|
bin | 11101110110101101100011… |
… | …011010001000010001111111 |
3 | 122012220110021201000112021121 |
4 | 131312231203122020101333 |
5 | 114202232233412000223 |
6 | 1143131452320011411 |
7 | 36441223354354114 |
oct | 3566554332102177 |
9 | 565813251015247 |
10 | 131303113000063 |
11 | 38923379250444 |
12 | 1288750aa60b67 |
13 | 5835aa45a98a4 |
14 | 245d166d6690b |
15 | 102a76693415d |
hex | 776b6368847f |
131303113000063 has 2 divisors, whose sum is σ = 131303113000064. Its totient is φ = 131303113000062.
The previous prime is 131303113000019. The next prime is 131303113000067. The reversal of 131303113000063 is 360000311303131.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-131303113000063 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (131303113000067) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65651556500031 + 65651556500032.
It is an arithmetic number, because the mean of its divisors is an integer number (65651556500032).
Almost surely, 2131303113000063 is an apocalyptic number.
131303113000063 is a deficient number, since it is larger than the sum of its proper divisors (1).
131303113000063 is an equidigital number, since it uses as much as digits as its factorization.
131303113000063 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 1458, while the sum is 25.
Adding to 131303113000063 its reverse (360000311303131), we get a palindrome (491303424303194).
The spelling of 131303113000063 in words is "one hundred thirty-one trillion, three hundred three billion, one hundred thirteen million, sixty-three", and thus it is an aban number.
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