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131303301211253 is a prime number
BaseRepresentation
bin11101110110101101101110…
…101000000110010001110101
3122012220110202211011122111102
4131312231232220012101311
5114202233130102230003
61143131523122015445
736441231131211563
oct3566555650062165
9565813684148442
10131303301211253
1138923465511286
1212887561aa7585
135835b04597062
14245d183d5aa33
15102a778210588
hex776b6ea06475

131303301211253 has 2 divisors, whose sum is σ = 131303301211254. Its totient is φ = 131303301211252.

The previous prime is 131303301211183. The next prime is 131303301211261. The reversal of 131303301211253 is 352112103303131.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 123233599729969 + 8069701481284 = 11101063^2 + 2840722^2 .

It is an emirp because it is prime and its reverse (352112103303131) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 131303301211253 - 214 = 131303301194869 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (131303301211853) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65651650605626 + 65651650605627.

It is an arithmetic number, because the mean of its divisors is an integer number (65651650605627).

Almost surely, 2131303301211253 is an apocalyptic number.

It is an amenable number.

131303301211253 is a deficient number, since it is larger than the sum of its proper divisors (1).

131303301211253 is an equidigital number, since it uses as much as digits as its factorization.

131303301211253 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 4860, while the sum is 29.

Adding to 131303301211253 its reverse (352112103303131), we get a palindrome (483415404514384).

The spelling of 131303301211253 in words is "one hundred thirty-one trillion, three hundred three billion, three hundred one million, two hundred eleven thousand, two hundred fifty-three".