131304043401397 has 2 divisors, whose sum is σ = 131304043401398. Its totient is φ = 131304043401396.

The previous prime is 131304043401389. The next prime is 131304043401439. The reversal of 131304043401397 is 793104340403131.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 106529522686596 + 24774520714801 = 10321314^2 + 4977401^2 .

It is an emirp because it is prime and its reverse (793104340403131) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 131304043401397 - 2³ = 131304043401389 is a prime.

It is a super-3 number, since 3×131304043401397³ (a number of 43 digits) contains 333 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (131304043401367) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65652021700698 + 65652021700699.

It is an arithmetic number, because the mean of its divisors is an integer number (65652021700699).

Almost surely, 2^{131304043401397} is an apocalyptic number.

It is an amenable number.

131304043401397 is a deficient number, since it is larger than the sum of its proper divisors (1).

131304043401397 is an equidigital number, since it uses as much as digits as its factorization.

131304043401397 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 326592, while the sum is 43.

The spelling of 131304043401397 in words is "one hundred thirty-one trillion, three hundred four billion, forty-three million, four hundred one thousand, three hundred ninety-seven".