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13130444413001 is a prime number
BaseRepresentation
bin1011111100010010101101…
…1110011001100001001001
31201111020222020200021221002
42333010223132121201021
53210112122232204001
643532013133024345
72523433436665436
oct277045336314111
951436866607832
1013130444413001
1142026546199a3
1215809273250b5
13743270951906
14335734536b8d
1517b84653346b
hexbf12b799849

13130444413001 has 2 divisors, whose sum is σ = 13130444413002. Its totient is φ = 13130444413000.

The previous prime is 13130444412979. The next prime is 13130444413061. The reversal of 13130444413001 is 10031444403131.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 8900532357376 + 4229912055625 = 2983376^2 + 2056675^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-13130444413001 is a prime.

It is not a weakly prime, because it can be changed into another prime (13130444413061) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6565222206500 + 6565222206501.

It is an arithmetic number, because the mean of its divisors is an integer number (6565222206501).

Almost surely, 213130444413001 is an apocalyptic number.

It is an amenable number.

13130444413001 is a deficient number, since it is larger than the sum of its proper divisors (1).

13130444413001 is an equidigital number, since it uses as much as digits as its factorization.

13130444413001 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 6912, while the sum is 29.

Adding to 13130444413001 its reverse (10031444403131), we get a palindrome (23161888816132).

The spelling of 13130444413001 in words is "thirteen trillion, one hundred thirty billion, four hundred forty-four million, four hundred thirteen thousand, one".