Base | Representation |
---|---|
bin | 1011111100010010101101… |
… | …1110100001001011110011 |
3 | 1201111020222020201220000010 |
4 | 2333010223132201023303 |
5 | 3210112122234210103 |
6 | 43532013133430003 |
7 | 2523433440156126 |
oct | 277045336411363 |
9 | 51436866656003 |
10 | 13130444444403 |
11 | 4202654640550 |
12 | 158092733b303 |
13 | 743270962cb0 |
14 | 3357345443bd |
15 | 17b84653c903 |
hex | bf12b7a12f3 |
13130444444403 has 32 divisors (see below), whose sum is σ = 21231451809792. Its totient is φ = 7108745011200.
The previous prime is 13130444444389. The next prime is 13130444444407. The reversal of 13130444444403 is 30444444403131.
It is not a de Polignac number, because 13130444444403 - 216 = 13130444378867 is a prime.
It is a Harshad number since it is a multiple of its sum of digits (39).
It is not an unprimeable number, because it can be changed into a prime (13130444444407) by changing a digit.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 493649550 + ... + 493676147.
It is an arithmetic number, because the mean of its divisors is an integer number (663482869056).
Almost surely, 213130444444403 is an apocalyptic number.
13130444444403 is a gapful number since it is divisible by the number (13) formed by its first and last digit.
13130444444403 is a deficient number, since it is larger than the sum of its proper divisors (8101007365389).
13130444444403 is a wasteful number, since it uses less digits than its factorization.
13130444444403 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 987325755.
The product of its (nonzero) digits is 442368, while the sum is 39.
Adding to 13130444444403 its reverse (30444444403131), we get a palindrome (43574888847534).
The spelling of 13130444444403 in words is "thirteen trillion, one hundred thirty billion, four hundred forty-four million, four hundred forty-four thousand, four hundred three".
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