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1313050504433 is a prime number
BaseRepresentation
bin10011000110110111111…
…010001010110011110001
311122112012202011202202012
4103012313322022303301
5133003111412120213
62443112421132305
7163602421064303
oct23066772126361
94575182152665
101313050504433
11466952862348
12192589b5a095
1396a87aa0005
14477a28dd973
152424ea014a8
hex131b7e8acf1

1313050504433 has 2 divisors, whose sum is σ = 1313050504434. Its totient is φ = 1313050504432.

The previous prime is 1313050504357. The next prime is 1313050504463. The reversal of 1313050504433 is 3344050503131.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 981956137969 + 331094366464 = 990937^2 + 575408^2 .

It is a cyclic number.

It is not a de Polignac number, because 1313050504433 - 222 = 1313046310129 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 1313050504433.

It is not a weakly prime, because it can be changed into another prime (1313050504463) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 656525252216 + 656525252217.

It is an arithmetic number, because the mean of its divisors is an integer number (656525252217).

Almost surely, 21313050504433 is an apocalyptic number.

It is an amenable number.

1313050504433 is a deficient number, since it is larger than the sum of its proper divisors (1).

1313050504433 is an equidigital number, since it uses as much as digits as its factorization.

1313050504433 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 32400, while the sum is 32.

The spelling of 1313050504433 in words is "one trillion, three hundred thirteen billion, fifty million, five hundred four thousand, four hundred thirty-three".