13131002301233 has 4 divisors (see below), whose sum is σ = 13131166095360. Its totient is φ = 13130838507108.

The previous prime is 13131002301019. The next prime is 13131002301257. The reversal of 13131002301233 is 33210320013131.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 13131002301233 - 2¹² = 13131002297137 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 13131002301199 and 13131002301208.

It is not an unprimeable number, because it can be changed into a prime (13131002301533) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 81776753 + ... + 81937166.

It is an arithmetic number, because the mean of its divisors is an integer number (3282791523840).

Almost surely, 2^{13131002301233} is an apocalyptic number.

It is an amenable number.

13131002301233 is a deficient number, since it is larger than the sum of its proper divisors (163794127).

13131002301233 is an equidigital number, since it uses as much as digits as its factorization.

13131002301233 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 163794126.

The product of its (nonzero) digits is 972, while the sum is 23.

Adding to 13131002301233 its reverse (33210320013131), we get a palindrome (46341322314364).

The spelling of 13131002301233 in words is "thirteen trillion, one hundred thirty-one billion, two million, three hundred one thousand, two hundred thirty-three".