131310130003 has 4 divisors (see below), whose sum is σ = 141410909248. Its totient is φ = 121209350760.

The previous prime is 131310129989. The next prime is 131310130013. The reversal of 131310130003 is 300031013131.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 131310130003 - 2⁵ = 131310129971 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (131310130013) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 5050389603 + ... + 5050389628.

It is an arithmetic number, because the mean of its divisors is an integer number (35352727312).

Almost surely, 2^131310130003 is an apocalyptic number.

131310130003 is a gapful number since it is divisible by the number (13) formed by its first and last digit.

131310130003 is a deficient number, since it is larger than the sum of its proper divisors (10100779245).

131310130003 is a wasteful number, since it uses less digits than its factorization.

131310130003 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 10100779244.

The product of its (nonzero) digits is 81, while the sum is 16.

Adding to 131310130003 its reverse (300031013131), we get a palindrome (431341143134).

The spelling of 131310130003 in words is "one hundred thirty-one billion, three hundred ten million, one hundred thirty thousand, three".