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13131014244403 = 111398587975307
BaseRepresentation
bin1011111100010100110101…
…1100001000100000110011
31201111022102221220201122211
42333011031130020200303
53210114304121310103
643532145450312551
72523453526324456
oct277051534104063
951438387821584
1013131014244403
114202917241740
121580a66128757
13743331a16863
1433578a0a949d
1517b87b59236d
hexbf14d708833

13131014244403 has 8 divisors (see below), whose sum is σ = 14427798517440. Its totient is φ = 11851405922280.

The previous prime is 13131014244391. The next prime is 13131014244479. The reversal of 13131014244403 is 30444241013131.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 13131014244403 - 217 = 13131014113331 is a prime.

It is not an unprimeable number, because it can be changed into a prime (13131014245403) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 4293986125 + ... + 4293989182.

It is an arithmetic number, because the mean of its divisors is an integer number (1803474814680).

Almost surely, 213131014244403 is an apocalyptic number.

13131014244403 is a deficient number, since it is larger than the sum of its proper divisors (1296784273037).

13131014244403 is a wasteful number, since it uses less digits than its factorization.

13131014244403 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 8587975457.

The product of its (nonzero) digits is 13824, while the sum is 31.

Adding to 13131014244403 its reverse (30444241013131), we get a palindrome (43575255257534).

The spelling of 13131014244403 in words is "thirteen trillion, one hundred thirty-one billion, fourteen million, two hundred forty-four thousand, four hundred three".

Divisors: 1 11 139 1529 8587975307 94467728377 1193728567673 13131014244403