13131044013167 has 2 divisors, whose sum is σ = 13131044013168. Its totient is φ = 13131044013166.

The previous prime is 13131044013083. The next prime is 13131044013209. The reversal of 13131044013167 is 76131044013131.

It is a strong prime.

It is an emirp because it is prime and its reverse (76131044013131) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 13131044013167 - 2³² = 13126749045871 is a prime.

It is a super-3 number, since 3×13131044013167³ (a number of 40 digits) contains 333 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (13131044010167) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6565522006583 + 6565522006584.

It is an arithmetic number, because the mean of its divisors is an integer number (6565522006584).

Almost surely, 2^{13131044013167} is an apocalyptic number.

13131044013167 is a deficient number, since it is larger than the sum of its proper divisors (1).

13131044013167 is an equidigital number, since it uses as much as digits as its factorization.

13131044013167 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 18144, while the sum is 35.

Adding to 13131044013167 its reverse (76131044013131), we get a palindrome (89262088026298).

The spelling of 13131044013167 in words is "thirteen trillion, one hundred thirty-one billion, forty-four million, thirteen thousand, one hundred sixty-seven".