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131310993834481 is a prime number
BaseRepresentation
bin11101110110110100111001…
…001001001000000111110001
3122012221012121221012101201211
4131312310321021020013301
5114202344403410200411
61143135234321400121
736441622560346546
oct3566647111100761
9565835557171654
10131310993834481
1138926752826a3a
1212888b4a199041
13583675c228816
14245d6b3890bcd
15102aa78741221
hex776d392481f1

131310993834481 has 2 divisors, whose sum is σ = 131310993834482. Its totient is φ = 131310993834480.

The previous prime is 131310993834467. The next prime is 131310993834613. The reversal of 131310993834481 is 184438399013131.

It is a happy number.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 120769549830400 + 10541444004081 = 10989520^2 + 3246759^2 .

It is a cyclic number.

It is not a de Polignac number, because 131310993834481 - 221 = 131310991737329 is a prime.

It is a super-2 number, since 2×1313109938344812 (a number of 29 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (131310993834421) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65655496917240 + 65655496917241.

It is an arithmetic number, because the mean of its divisors is an integer number (65655496917241).

Almost surely, 2131310993834481 is an apocalyptic number.

It is an amenable number.

131310993834481 is a deficient number, since it is larger than the sum of its proper divisors (1).

131310993834481 is an equidigital number, since it uses as much as digits as its factorization.

131310993834481 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 6718464, while the sum is 58.

The spelling of 131310993834481 in words is "one hundred thirty-one trillion, three hundred ten billion, nine hundred ninety-three million, eight hundred thirty-four thousand, four hundred eighty-one".