Base | Representation |
---|---|
bin | 11101110110110100111111… |
… | …100010110100000001110111 |
3 | 122012221012220102021201100221 |
4 | 131312310333202310001313 |
5 | 114202400113403344343 |
6 | 1143135253115315211 |
7 | 36441625333246564 |
oct | 3566647742640167 |
9 | 565835812251327 |
10 | 131311101231223 |
11 | 389267a840a781 |
12 | 12888b7a14bb07 |
13 | 583677855bca4 |
14 | 245d6c3c4986b |
15 | 102aa82da75ed |
hex | 776d3f8b4077 |
131311101231223 has 16 divisors (see below), whose sum is σ = 147586102836480. Its totient is φ = 116224055950464.
The previous prime is 131311101231199. The next prime is 131311101231493. The reversal of 131311101231223 is 322132101113131.
It is a cyclic number.
It is not a de Polignac number, because 131311101231223 - 29 = 131311101230711 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (131311101211223) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 3493970386 + ... + 3494007967.
It is an arithmetic number, because the mean of its divisors is an integer number (9224131427280).
Almost surely, 2131311101231223 is an apocalyptic number.
131311101231223 is a deficient number, since it is larger than the sum of its proper divisors (16275001605257).
131311101231223 is a wasteful number, since it uses less digits than its factorization.
131311101231223 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 6987978438.
The product of its (nonzero) digits is 648, while the sum is 25.
Adding to 131311101231223 its reverse (322132101113131), we get a palindrome (453443202344354).
The spelling of 131311101231223 in words is "one hundred thirty-one trillion, three hundred eleven billion, one hundred one million, two hundred thirty-one thousand, two hundred twenty-three".
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