13131112201441 has 4 divisors (see below), whose sum is σ = 14141197755412. Its totient is φ = 12121026647472.

The previous prime is 13131112201439. The next prime is 13131112201499. The reversal of 13131112201441 is 14410221113131.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 3706795492416 + 9424316709025 = 1925304^2 + 3069905^2 .

It is a cyclic number.

It is not a de Polignac number, because 13131112201441 - 2¹ = 13131112201439 is a prime.

It is a super-2 number, since 2×13131112201441² (a number of 27 digits) contains 22 as substring.

It is not an unprimeable number, because it can be changed into a prime (13131112202441) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 505042776966 + ... + 505042776991.

It is an arithmetic number, because the mean of its divisors is an integer number (3535299438853).

Almost surely, 2^{13131112201441} is an apocalyptic number.

It is an amenable number.

13131112201441 is a deficient number, since it is larger than the sum of its proper divisors (1010085553971).

13131112201441 is a wasteful number, since it uses less digits than its factorization.

13131112201441 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1010085553970.

The product of its (nonzero) digits is 576, while the sum is 25.

Adding to 13131112201441 its reverse (14410221113131), we get a palindrome (27541333314572).

The spelling of 13131112201441 in words is "thirteen trillion, one hundred thirty-one billion, one hundred twelve million, two hundred one thousand, four hundred forty-one".