131311130210003 has 4 divisors (see below), whose sum is σ = 131311164840240. Its totient is φ = 131311095579768.

The previous prime is 131311130209951. The next prime is 131311130210021. The reversal of 131311130210003 is 300012031113131.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 131311130210003 - 2²⁴ = 131311113432787 is a prime.

It is a super-2 number, since 2×131311130210003² (a number of 29 digits) contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (131311130210053) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 10813700 + ... + 19482257.

It is an arithmetic number, because the mean of its divisors is an integer number (32827791210060).

Almost surely, 2^{131311130210003} is an apocalyptic number.

131311130210003 is a deficient number, since it is larger than the sum of its proper divisors (34630237).

131311130210003 is an equidigital number, since it uses as much as digits as its factorization.

131311130210003 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 34630236.

The product of its (nonzero) digits is 162, while the sum is 20.

Adding to 131311130210003 its reverse (300012031113131), we get a palindrome (431323161323134).

The spelling of 131311130210003 in words is "one hundred thirty-one trillion, three hundred eleven billion, one hundred thirty million, two hundred ten thousand, three".