131311130210021 has 2 divisors, whose sum is σ = 131311130210022. Its totient is φ = 131311130210020.

The previous prime is 131311130209951. The next prime is 131311130210053. The reversal of 131311130210021 is 120012031113131.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 84814687641121 + 46496442568900 = 9209489^2 + 6818830^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-131311130210021 is a prime.

It is a super-2 number, since 2×131311130210021² (a number of 29 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 131311130209975 and 131311130210002.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (131311130210321) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65655565105010 + 65655565105011.

It is an arithmetic number, because the mean of its divisors is an integer number (65655565105011).

Almost surely, 2^{131311130210021} is an apocalyptic number.

It is an amenable number.

131311130210021 is a deficient number, since it is larger than the sum of its proper divisors (1).

131311130210021 is an equidigital number, since it uses as much as digits as its factorization.

131311130210021 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 108, while the sum is 20.

Adding to 131311130210021 its reverse (120012031113131), we get a palindrome (251323161323152).

The spelling of 131311130210021 in words is "one hundred thirty-one trillion, three hundred eleven billion, one hundred thirty million, two hundred ten thousand, twenty-one".