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1313111312243 = 1969111121697
BaseRepresentation
bin10011000110111011100…
…010001000011101110011
311122112100222121010101022
4103012323202020131303
5133003222443442433
62443122432330055
7163604056664453
oct23067342103563
94575328533338
101313111312243
11466984115135
121925a63a392b
1396a97570873
14477aaa0bd63
1524255013698
hex131bb888773

1313111312243 has 4 divisors (see below), whose sum is σ = 1382222433960. Its totient is φ = 1244000190528.

The previous prime is 1313111312081. The next prime is 1313111312263. The reversal of 1313111312243 is 3422131113131.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 1313111312243 - 232 = 1308816344947 is a prime.

It is a super-2 number, since 2×13131113122432 (a number of 25 digits) contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (1313111312263) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 34555560830 + ... + 34555560867.

It is an arithmetic number, because the mean of its divisors is an integer number (345555608490).

Almost surely, 21313111312243 is an apocalyptic number.

1313111312243 is a deficient number, since it is larger than the sum of its proper divisors (69111121717).

1313111312243 is an equidigital number, since it uses as much as digits as its factorization.

1313111312243 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 69111121716.

The product of its digits is 1296, while the sum is 26.

Adding to 1313111312243 its reverse (3422131113131), we get a palindrome (4735242425374).

The spelling of 1313111312243 in words is "one trillion, three hundred thirteen billion, one hundred eleven million, three hundred twelve thousand, two hundred forty-three".

Divisors: 1 19 69111121697 1313111312243