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1313111322000 = 243253431169259
BaseRepresentation
bin10011000110111011100…
…010001010110110010000
311122112100222121121202200
4103012323202022312100
5133003222444301000
62443122432443200
7163604060035062
oct23067342126620
94575328547680
101313111322000
114669841214a5
121925a63a9500
1396a9757513a
14477aaa11732
1524255016500
hex131bb88ad90

1313111322000 has 240 divisors, whose sum is σ = 4596928277760. Its totient is φ = 349348512000.

The previous prime is 1313111321999. The next prime is 1313111322031. The reversal of 1313111322000 is 2231113131.

1313111322000 is a `hidden beast` number, since 1 + 31 + 311 + 1 + 322 + 0 + 0 + 0 = 666.

It is a tau number, because it is divible by the number of its divisors (240).

It is a super-2 number, since 2×13131113220002 (a number of 25 digits) contains 22 as substring.

It is a Harshad number since it is a multiple of its sum of digits (18).

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 47 ways as a sum of consecutive naturals, for example, 7673371 + ... + 7842629.

It is an arithmetic number, because the mean of its divisors is an integer number (19153867824).

Almost surely, 21313111322000 is an apocalyptic number.

1313111322000 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 1313111322000, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (2298464138880).

1313111322000 is an abundant number, since it is smaller than the sum of its proper divisors (3283816955760).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

1313111322000 is a wasteful number, since it uses less digits than its factorization.

1313111322000 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 169719 (or 169700 counting only the distinct ones).

The product of its (nonzero) digits is 108, while the sum is 18.

Adding to 1313111322000 its reverse (2231113131), we get a palindrome (1315342435131).

The spelling of 1313111322000 in words is "one trillion, three hundred thirteen billion, one hundred eleven million, three hundred twenty-two thousand".