1313111550041 has 2 divisors, whose sum is σ = 1313111550042. Its totient is φ = 1313111550040.

The previous prime is 1313111550031. The next prime is 1313111550043. The reversal of 1313111550041 is 1400551113131.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 726294268441 + 586817281600 = 852229^2 + 766040^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-1313111550041 is a prime.

Together with 1313111550043, it forms a pair of twin primes.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (1313111550043) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 656555775020 + 656555775021.

It is an arithmetic number, because the mean of its divisors is an integer number (656555775021).

Almost surely, 2^{1313111550041} is an apocalyptic number.

It is an amenable number.

1313111550041 is a deficient number, since it is larger than the sum of its proper divisors (1).

1313111550041 is an equidigital number, since it uses as much as digits as its factorization.

1313111550041 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 900, while the sum is 26.

Adding to 1313111550041 its reverse (1400551113131), we get a palindrome (2713662663172).

The spelling of 1313111550041 in words is "one trillion, three hundred thirteen billion, one hundred eleven million, five hundred fifty thousand, forty-one".